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  • P1000A+B Problem
    限制 : 时间限制 : 3000 MS   空间限制 : 65536 KB  SPJ
    问题描述

    计算 a+b

    输入格式

    输入两个整数 $ a,b (-1000000\le a,b \le 1000000) $

    输出格式

    输出 a+b的值

    样例输入

    123 456

    样例输出

    579

    提示

    Q: Where are the input and the output?
    A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout.
    You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer".
    User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer"if you try to do so.

    Here is a sample solution to problem A+B using C++/G++:

    #include <iostream>
    using namespace std;
    int main()
    {
        int a,b;
        cin >> a >> b;
        cout << a+b << endl;
        return 0;
    }
    

    It's important that the return type of main() must be int and its value must be 0, otherwise you may get compilation error or runtime error.

    Here is a sample solution to problem A+B using C/GCC:

    #include <stdio.h>
    int main()
    {
        int a,b;
        scanf("%d %d",&a, &b);
        printf("%d\n",a+b);
        return 0;
    }
    

    Here is a sample solution to problem A+B using Pascal:

    program sum;
    var
      a,b: longint;
    begin
       readln(a,b);
       writeln(a+b);
    end.
    

    Here is a sample solution to problem A+B using Java:

    import java.io.*;
    import java.util.*;
    public class Main
    {
        public static void main(String args[]) throws Exception
        {
            Scanner cin=new Scanner(System.in);
            int a=cin.nextInt(),b=cin.nextInt();
            System.out.println(a+b);
        }
    }